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tec_server Technology Bot
Joined: 04 Nov 2002 Posts: 1746
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Posted: Wed Jul 27, 2005 1:47 pm Post subject: eye in the sky |
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eye in the sky (class 3 ship) (formerly known as illuminator)
this recon vessel is equipped with sophisticated surveilance technology, that scans the area for foreign fleet signatures like the deep scan probe.
it is only fully functioning in interaction with a pyramid-device at your base. it is exposed a strong radiation that interferes with every cloaking technology, so a fleet with it cannot be cloaked and on battle contact it will disintegrate
attack/life: 0/100
manpower: 300
researchtime: 2 h
buildingtime: 12 h
needed research:
pyramid-device
battle details:
1. fights
(battle engine syntax: f)
2. self destructs!
battlemessage: "explodes"
(battle engine syntax: sd,explodes,n) |
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admin Board Admin
Joined: 09 Jan 2002 Posts: 2938
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deenky Midshipman
Joined: 10 Feb 2010 Posts: 1
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Posted: Tue Feb 16, 2010 8:54 am Post subject: |
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How do I find the surface area of this hexagonal pyramid? It is a regular hexagonal pyramid. One edge of the base is 5.5cm, and one lateral edge is 9cm. I am wondering how I would find the slant height of one face and the area of the base. |
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admin Board Admin
Joined: 09 Jan 2002 Posts: 2938
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Posted: Sat Feb 20, 2010 3:28 pm Post subject: |
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nice bot, i will leave this interesting question in here |
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colinthecorgi 1st Rear Admiral
Joined: 30 Nov 2007 Posts: 273
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Posted: Sat Feb 20, 2010 9:17 pm Post subject: |
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maybe I am a bit slow, but where does it say that the pyramid device is hexagonal?
Or do you just want the math for a hexagonal pyramid? |
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colinthecorgi 1st Rear Admiral
Joined: 30 Nov 2007 Posts: 273
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Posted: Sat Feb 20, 2010 9:24 pm Post subject: |
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A pyramid with a hexagonal base. The edge length of a hexagonal pyramid of height h is a special case of the formula for a regular n-gonal pyramid with n=6, given by
e=sqrt(h*h+a*a), where a is the length of a bottom edge
The volume of the hexagonal prism is
V=sqrt(3)*h*a*a/2
Weisstein, Eric W. "Hexagonal Pyramid." From MathWorld--A Wolfram Web Resource. http://mathworld.wolfram.com/HexagonalPyramid.html
Finding the bottom surface seems rather easy, no?
Since it is a symmetrical pyramid, all corner angles must be the same, in this case 120 degrees. So you can split the bottom surface into 6 identical triangles with all sides 5.5 by just drawing a line from all corners into the centre, no? So the corner angles must be 60 degrees for all the 6 separate triangles. Then is simple trig after that. |
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fungu Captain
Joined: 21 Dec 2001 Posts: 111
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Posted: Tue Sep 13, 2011 8:43 am Post subject: |
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selfdestruction???
is it nessesary ?
it is already very expensive! _________________ I AM fmfjjj Ruler of the planet Osusmu MCG 2713 |
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admin Board Admin
Joined: 09 Jan 2002 Posts: 2938
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Posted: Tue Sep 13, 2011 6:17 pm Post subject: |
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sure, otherwise it would make the deep scan probes obsolete |
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